College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.4 - Evaluating Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 435: 57

Answer

$\approx10.1449$

Work Step by Step

The value of $ \ln 27 $ is approximately $ 3.2958 $. The value of $ \ln943 $ is approximately $ 6.8491 $. Hence, the given expression, $ \ln 27+\ln943 $ evaluates to \begin{array}{l}\require{cancel} 3.2958+6.8491 \\\\ \approx10.1449 .\end{array}
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