College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.4 - Evaluating Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 434: 18

Answer

$\approx-2.2596$

Work Step by Step

Using $\log_b a=\dfrac{\log a}{\log b}$ or the Change-of-Base Formula and the laws of logarithms, the given expression, $ \log 0.0055 ,$ evaluates to \begin{array}{l}\require{cancel} \dfrac{\log 0.0055}{\log 10} \\\\\approx \dfrac{-2.2596}{1} \\\\ \approx-2.2596 .\end{array}
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