College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 423: 32

Answer

$3$

Work Step by Step

Rewrite the equation using the definition of logarithm. $(\frac{1}{3})^{-2}=x+6$ Raise $(\frac{1}{3})^{-2}$ to the -1 power. $3^2=x+6$ Simplify. $x=3$
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