College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 423: 23

Answer

$\pm\frac{1}{5}$

Work Step by Step

Rewrite in exponential form. $x^{-2}=5^2$ Raise each side to the $-\frac{1}{2}$ power. $(x^{-2})^{-1(\frac{1}{2})}=x$. First take the square root. $x^{-1}=\pm5$ Then raise to the negative first power. $x=\pm\frac{1}{5}$
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