College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 422: 12

Answer

$1$

Work Step by Step

Because $a^0=1$ always. Division explains. When dividing exponents you use subtraction to find the solution. $\frac{a^2}{a^2}=a^{2-2}=a^0$. The fraction $\frac{a^2}{a^2}$ obviously evaluates to 1 and so does $a^0$ since it is equivalent.
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