College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.2 - Exponential Functions - 4.2 Exercises - Page 410: 82

Answer

$x=9$

Work Step by Step

Raising both sides to the power of $ \dfrac{2}{3} $, the solution to the given equation, $ x^{3/2}=27 ,$ is \begin{array}{l}\require{cancel} \left( x^{\frac{3}{2}} \right)^{\frac{2}{3}}=\left( 3^3 \right)^{\frac{2}{3}} \\\\ x^{\frac{3}{2}\left(\frac{2}{3}\right)}=3^{3\left(\frac{2}{3}\right)} \\\\ x^{1}=3^{2} \\\\ x=9 .\end{array}
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