College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.2 - Exponential Functions - 4.2 Exercises - Page 409: 53

Answer

$\dfrac{1}{a}$

Work Step by Step

The laws of exponents says: $a^{-1}=\frac{1}{a}$ Therefore, $f(x)=a^{-x}=(a^{-1})^{x}=\left(\frac{1}{a}\right)^x$
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