Answer
$(x-2)^2+(y+1)^2=3^2=9$
See graph.
Work Step by Step
A circle has the form:
$(x-h)^2+(y-k)^2=r^2$ with center $(h,k)$ and radius $r$
Our center is $(2,-1)$ and radius is $3$, so we have:
$(x-2)^2+(y+1)^2=3^2=9$
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