College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.5 - Equations of Lines and Linear Models - Summary Exercises on Graphs, Circles, Functions, and Equations - Page 231: 11

Answer

$(x-2)^2+(y+1)^2=3^2=9$ See graph.

Work Step by Step

A circle has the form: $(x-h)^2+(y-k)^2=r^2$ with center $(h,k)$ and radius $r$ Our center is $(2,-1)$ and radius is $3$, so we have: $(x-2)^2+(y+1)^2=3^2=9$
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