College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.4 - Linear Functions - 2.4 Exercises - Page 215: 80

Answer

$\sqrt{10}$

Work Step by Step

We find the distance between the first two points, $(0,-6)$ and $(1,-3)$ by using the distance formula: $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2)}$ $=\sqrt{(1-0)^{2}+[-3-(-6)]^{2}}$ $=\sqrt{1^{2}+3^{2}}$ $=\sqrt{1+9}$ $=\sqrt{10}$
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