College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.3 - Functions - 2.3 Exercises - Page 200: 47

Answer

$g\left( \dfrac{1}{2} \right)=\dfrac{11}{4}$

Work Step by Step

Substituting $x$ with $ \dfrac{1}{2} $ in the given function, $ g(x)=-x^2+4x+1 ,$ then, \begin{array}{l}\require{cancel} g\left( \dfrac{1}{2} \right)=-\left( \dfrac{1}{2} \right)^2+4\left( \dfrac{1}{2} \right)+1 \\\\ g\left( \dfrac{1}{2} \right)=-\dfrac{1}{4}+2+1 \\\\ g\left( \dfrac{1}{2} \right)=\dfrac{11}{4} .\end{array}
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