College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.2 - Circles - 2.2 Exercises - Page 185: 9

Answer

$(x-5)^{2}+(y+4)^{2}=49$

Work Step by Step

First, we put the given information into the center-radius equation for a circle given in the chapter. Place the $x$ value into the $h$ in the equation and the $y$ in the $k$. The $R$ is the radius. $(x-(5))^{2}+(y-(-4))^{2}=7^{2}$ $(x-5)^{2}+(y+4)^{2}=49$
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