Answer
$x^{2}+(y-4)^{2}=16$
Work Step by Step
First, we put the given information into the center-radius equation for a circle given in the chapter. Place the $x$ value into the $h$ in the equation and the $y$ in the $k$. The $R$ is the radius.
$(x-(0))^{2}+(y-(4))^{2}=4^{2}$
$x^{2}+(y-4)^{2}=16$