College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.2 - Circles - 2.2 Exercises - Page 185: 5

Answer

$x^{2}+(y-4)^{2}=16$

Work Step by Step

First, we put the given information into the center-radius equation for a circle given in the chapter. Place the $x$ value into the $h$ in the equation and the $y$ in the $k$. The $R$ is the radius. $(x-(0))^{2}+(y-(4))^{2}=4^{2}$ $x^{2}+(y-4)^{2}=16$
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