Answer
$(x-3)^{2}+y^{2}=9$
Work Step by Step
First, we put the given information into the center-radius equation for a circle given in the chapter. Place the $x$ value into the $h$ in the equation and the $y$ in the $k$. The $R$ is the radius.
$(x-(3))^{2}+(y-(0))^{2}=3^{2}$
$(x-3)^{2}+y^{2}=9$