Answer
$(x+2)^{2}+(y-2)^{2}=4$
Work Step by Step
First, we put the given information into the center-radius equation for a circle given in the chapter. Place the $x$ value into the $h$ in the equation and the $y$ in the $k$. The $R$ is the radius.
$(x-(-2))^{2}+(y-(2))^{2}=2^{2}$
$(x+2)^{2}+(y-2)^{2}=4$