College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.2 - Circles - 2.2 Exercises - Page 185: 12

Answer

$(x+\sqrt 3)^{2}+(y+\sqrt 3)^{2}=3$

Work Step by Step

First, we put the given information into the center-radius equation for a circle given in the chapter. Place the $x$ value into the $h$ in the equation and the $y$ in the $k$. The $R$ is the radius. $(x-(-\sqrt 3))^{2}+(y-(-\sqrt 3))^{2}=\sqrt 3^{2}$ $(x+\sqrt 3)^{2}+(y+\sqrt 3)^{2}=3$
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