Answer
$(x-\sqrt 2)^{2}+(y-\sqrt 2)^{2}=2$
Work Step by Step
First, we put the given information into the center-radius equation for a circle given in the chapter. Place the $x$ value into the $h$ in the equation and the $y$ in the $k$. The $R$ is the radius.
$(x-(\sqrt 2))^{2}+(y-(\sqrt 2))^{2}=\sqrt 2^{2}$
$(x-\sqrt 2)^{2}+(y-\sqrt 2)^{2}=2$