College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Review Exercises - Page 277: 56

Answer

$m=\dfrac{1}{5}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Convert the given equation, $ x-5y=0 ,$ to the Slope-Intercept Form to identify the slope of the line. $\bf{\text{Solution Details:}}$ Using the properties of equality, in the Slope-Intercept Form which is given by $y=mx+b,$ the given equation is equivalent to \begin{array}{l}\require{cancel} x-5y=0 \\\\ -5y=-x \\\\ y=\dfrac{-x}{-5} \\\\ y=\dfrac{1}{5}x .\end{array} Since $m$ is the slope in the equation $y=mx+b,$ then the slope of the linear equation above is $ m=\dfrac{1}{5} .$
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