College Algebra (11th Edition)

Since for any $a\gt0$, $|x|\gt a$ implies $x\gt a$ or $x\lt-a$, then the given inequality, $|x|\gt7 ,$ is equivalent to \begin{array}{l}\require{cancel} x\gt7 \\\\\text{OR}\\\\ x\lt-7 .\end{array} Hence, the graph is $\text{ Choice E }.$