Answer
(A) $(x-3)^{2}\geq 0$
Work Step by Step
We know that in (A), $(x-3)^{2}$ is either positive or zero (because it is squared). This means that $(x-3)^{2}\geq0$ for all real numbers. Thus the solution to $(x-3)^{2}\geq0$ is all real numbers, or $(-\infty,\ \infty)$.