Answer
$$x\leq\frac{48}{7}$$
$$(-\infty, \frac{48}{7}]$$
Work Step by Step
$$\frac{1}{3}x+\frac{2}{5}x-\frac{1}{2}x-\frac{3}{2}\leq\frac{1}{10}$$
$$30(\frac{1}{3}x+\frac{2}{5}x-\frac{1}{2}x-\frac{3}{2})\leq(30)(\frac{1}{10})$$
$$10x+12x-15x\leq3+45$$
$$7x\leq48$$
$$x\leq\frac{48}{7}$$