College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.6 - Other Types of Equations and Applications - Summary Exercises on Solving Equations - Page 136: 15

Answer

$x=4$

Work Step by Step

We are given: $\sqrt[6]{2x+1}=\sqrt[6]{9}$ We raise both sides to the power of 6: $(\sqrt[6]{2x+1})^{6}=(\sqrt[6]{9})^{6} \\2x+1=9$ Subtract $1$ to both sides:: $2x=8$ Divide both sdies by $2$ $x=4$
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