College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.6 - Other Types of Equations and Applications - 1.6 Exercises - Page 136: 97

Answer

$h=\displaystyle \frac{d^{2}}{k^{2}}$

Work Step by Step

We solve this equation for $h$: $d=k\sqrt{h}$ First divide by $k$: $\frac{d}{k}=\sqrt{h}$ Then square both sides: $\frac{d^{2}}{k^{2}}=h$ Thus: $h=\displaystyle \frac{d^{2}}{k^{2}}$
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