College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.6 - Other Types of Equations and Applications - 1.6 Exercises - Page 135: 58

Answer

$x=-\dfrac{2}{3}$

Work Step by Step

Raising both sides to the $\text{ third }$ power, the solution of the given equation, $ \sqrt[3]{2x}=\sqrt[3]{5x+2} ,$ \begin{array}{l}\require{cancel} 2x=5x+2 \\\\ 2x-5x=2 \\\\ -3x=2 \\\\ x=\dfrac{2}{-3} \\\\ x=-\dfrac{2}{3} .\end{array}
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