College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.6 - Other Types of Equations and Applications - 1.6 Exercises - Page 134: 11

Answer

No solution

Work Step by Step

$$\frac{-2}{x-3}+\frac{3}{x+3}=\frac{-12}{(x+3)(x-3)}$$ $$(x+3)(x-3)(\frac{-2}{x-3}+\frac{3}{x+3})=(x+3)(x-3)(\frac{-12}{(x+3)(x-3)})$$ $$-2(x+3)+3(x-3)=-12$$ $$-2x-6+3x-9=-12$$ $$x-15=-12$$ $$x=3$$ However, 3 is an extraneous solution. There is no solution.
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