College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.5 - Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 119: 15

Answer

The side lengths of the triangle are 6, 8 and 10.

Work Step by Step

$$x^2+(x+2)^2=(x+4)^2$$ $$x^2+x^2+4x+4=x^2+8x+16$$ $$2x^2+4x+4=x^2+8x+16$$ $$x^2-4x-12=0$$ $$(x-6)(x+2)=0$$ $$x=6,-2$$ Length can not be negative, so x=6. The side lengths of the triangle are 6, 8 and 10.
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