College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.2 - Applications and Modeling with Linear Equations - 1.2 Exercises - Page 93: 14

Answer

The length is 15.7 ft and the width is 9.8 ft.

Work Step by Step

P is the perimeter, l is the length, and w is the width. $P=51=2w+2l$, and $l=w+5.9$ Substitute. $51=2w+2(w+5.9)$ Distribute. $51=2w+2w=11.8$ Combine like terms. $51=4w+11.8$ Subtract 11.8 from both sides. $39.2=4w$ Divide both sides by 4. $9.8=w$ Substitute the value of w to find the length. $l=(9.8)+5.9$ Add. $l=15.7$ Check. $2(15.7)+2(9.8)=51$
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