Answer
$x=\left\{ -\sqrt{29},\sqrt{29} \right\}$
Work Step by Step
$\bf{\text{Solution Outline:}}$
To solve the given equation, $
x^2-29=0
,$ convert it to the form $x^2=c.$ Then use the Square Root Principle.
$\bf{\text{Solution Details:}}$
Using the properties of equality, the equation above is equivalent to
\begin{array}{l}\require{cancel}
x^2=29
.\end{array}
Taking the square root of both sides (Square Root Principle), the equation above is equivalent to
\begin{array}{l}\require{cancel}
x=\pm\sqrt{29}
.\end{array}
The solutions are $
x=\left\{ -\sqrt{29},\sqrt{29} \right\}
.$