College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 79: 88

Answer

$\displaystyle \frac{3x+1}{2x^{1/2}}=\frac{3x+1}{2\sqrt{x}}$

Work Step by Step

We simplify: $\displaystyle \frac{1+x}{2x^{1/2}}+x^{1/2}=\frac{1+x}{2x^{1/2}}+x^{1/2}\frac{2x^{1/2}}{2x^{1/2}}=\frac{1+x+x^{1/2}*2x^{1/2}}{2x^{1/2}} =\frac{1+x+2x}{2x^{1/2}}=\frac{3x+1}{2x^{1/2}}=\frac{3x+1}{2\sqrt{x}}$
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