College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 78: 36

Answer

$-5\sqrt{3}$

Work Step by Step

Using the properties of radicals that we know, we simplify: $(2\sqrt{12})-(3\sqrt{27})=2\sqrt{4*3}-3\sqrt{9*3}=2*2\sqrt{3}-3*3\sqrt{3}=4\sqrt{3}-9\sqrt{3}=(4-9)\sqrt{3}=-5\sqrt{3}$
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