College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.7 - Rational Expressions - R.7 Assess Your Understanding: 12

Answer

$\dfrac{x+2}{x-2}; x \ne-2, 2$

Work Step by Step

Factor the numerator and the denominator completely to obtain: $=\dfrac{(x+2)(x+2)}{(x-2)(x+2)}$ Cancel the common factors to obtain: $\require{cancel} \\=\dfrac{\cancel{(x+2)}(x+2)}{(x-2)\cancel{(x+2)}} \\=\dfrac{x+2}{x-2}; x \ne-2, 2$ ($x$ cannot be $-2$ and $2$ because they will make the original expression undefined.)
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