College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises: 133

Answer

$(4x-3)(12x-3)$

Work Step by Step

We factor by grouping to obtain: $(4x-3)^{2}+x* 2(4x-3)* 4 =(4x-3)^{2}+8x(4x-3) =(4x-3)[(4x-3)^1+8x] =(4x-3)(4x-3+8x) =(4x-3)(12x-3) $
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