Answer
$(4x-3)(12x-3)$
Work Step by Step
We factor by grouping to obtain:
$(4x-3)^{2}+x* 2(4x-3)* 4
=(4x-3)^{2}+8x(4x-3)
=(4x-3)[(4x-3)^1+8x]
=(4x-3)(4x-3+8x)
=(4x-3)(12x-3)
$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises - Page 58: 133
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