College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises: 128

Answer

$(2x+1)(30x-19)$

Work Step by Step

We factor by grouping to obtain: $5(2x+1)^{2}+(5x-6)* 2(2x+1)* 2 =(2x+1)[5(2x+1)^1+(5x-6)* 4] =(2x+1)(10x+5+20x-24) =(2x+1)(30x-19)$
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