Answer
$2(3x+4)(9x+13)$
Work Step by Step
We factor by grouping to obtain:
$2(3x+4)^{2}+(2x+3)* 2(3x+4)* 3
=2(3x+4)[(3x+4)^1+(2x+3)* 3]
=2(3x+4)(3x+4+6x+9)
=2(3x+4)(9x+13)$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises - Page 58: 127
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