College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Exercises: 124

Answer

$(x-1)(x+1)(x-3)$

Work Step by Step

We factor by grouping to obtain: $x^{3}-3x^{2}-x+3=x^{2}(x-3)-1(x-3) =(x^{2}-1)(x-3) =(x-1)(x+1)(x-3)$
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