Answer
$x=-4$
Work Step by Step
If the sequence is geometric, there is a constant ratio between terms:
$\displaystyle \frac{x+2}{x}=\frac{x+3}{x+2}$
$(x+2)=x(x+3)$
$x^{2}+4x+4=x^{2}+3x$
$x+4=0$
$x=-4$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 9 - Section 9.3 - Geometric Sequences; Geometric Series - 9.3 Assess Your Understanding - Page 665: 83
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