College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Section 9.3 - Geometric Sequences; Geometric Series - 9.3 Assess Your Understanding - Page 664: 9

Answer

The sequence is geometric with a common ratio of $3$. The first four terms are: $s_1=3$ $s_2=9$ $s_3=27$ $s_4=3^4=3(3)(3)(3)=27(3)=81$

Work Step by Step

Substitute $1, 2, 3,$ and $4$ to $n$ in the given formula to : $s_1=3^1 = 3$ $s_2=3^2=3(3)=9$ $s_3=3^3=3(3)(3)=9(3)=27$ $s_4=3^4=3(3)(3)(3)=27(3)=81$ Notice the the next term is equal to $3$ times the current term. This means that a common ratio of $3$ exists and the sequence is geometric.
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