College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Section 9.1 - Sequences - 9.1 Assess Your Understanding: 71

Answer

$$\require{cancel} \sum_{k=1}^{40}k = 820$$

Work Step by Step

RECALL: $$\sum_{i=1}^{n}k = \dfrac{n(n+1)}{2}$$ Use the rule above to obtain: $$\require{cancel} \sum_{k=1}^{40}k = \dfrac{40(41)}{2}=820$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.