Answer
$$\sum_{k=1}^{40}5 =200$$
Work Step by Step
RECALL:
For any constant $c$,
$$\sum_{i=1}^{n}c = nc$$
Use the rule above to obtain:
$$\sum_{k=1}^{40}5 = 40(5) = 200$$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 9 - Section 9.1 - Sequences - 9.1 Assess Your Understanding - Page 648: 69
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