College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Section 9.1 - Sequences - 9.1 Assess Your Understanding - Page 647: 56

Answer

$1+3+5+7+\cdots+(2n-1)$

Work Step by Step

There are n terms, as the index k changes from 0 to n-1. The index k dictates how the terms are formed: $\displaystyle \sum_{k=0}^{n-1}(2k+1)=\\=(2(0)+1)+(2(1)+1)+(2(3)+1)+...+(2(n-1)+1)$ $=1+3+5+7+\cdots+(2n-1)$
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