Answer
$ 132$
Work Step by Step
RECALL:
(1) For any natural number $n$,
$n! = n(n-1)(n-2)(n-3)...$
(2) $0!=1$
Use the definition in (1) above to obtain:
$\require{cancel}
\dfrac{12!}{10!}
\\=\dfrac{12(11)(10)(9)(8)(7)(6)(5)(4)(3)(2)(1)}{10(9)(8)(7)(6)(5)(4)(3)(2)(1)}
\\=\dfrac{12(11){(10)(9)(8)(7)(6)(5)(4)(3)(2)(1)}}{10(9)(8)(7)(6)(5)(4)(3)(2)(1)}
\\=12(11)
\\= 132$
