College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.1 - Systems of Linear Equations: Substitution and Elimination - 8.1 Assess Your Understanding - Page 555: 38

Answer

$x=12$ $y=6$ $(12,6)$

Work Step by Step

$\frac{1}{3}x - \frac{3}{2}y = -5$ $(1)$ $\frac{3}{4}x + \frac{1}{3}y=11$ $(2)$ Multiply Equation $(1)$ by $\frac{1}{3}$ and Equation $(2)$ by $\frac{3}{2}$ $\frac{1}{9}x - \frac{1}{2}y = -\frac{5}{3}$ $(1)$ $\frac{9}{8}x + \frac{1}{2}y = \frac{33}{2}$ $(2)$ Add two equations together $(\frac{1}{9} + \frac{9}{8})x = -\frac{5}{3} + \frac{33}{2}$ $\frac{89}{72}x = \frac{89}{6}$ $x=12$ Substitute into Equation $(2)$ $\frac{1}{3}y = 11 - \frac{3}{4}(12)$ $\frac{1}{3}y=2$ $y=6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.