College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.1 - Systems of Linear Equations: Substitution and Elimination - 8.1 Assess Your Understanding - Page 555: 34

Answer

$x=\frac{1}{5}$ $y=\frac{3}{10}$ $(\frac{1}{5},\frac{3}{10})$

Work Step by Step

$3x-2y=0$ $(1)$ $5x+10y=4$ $(2)$ Multiply Equation $(1)$ by 5 $15x - 10y=0$ $(1)$ $5x+10y=4$ $(2)$ Add Equation $(1)$ and Equation $(2)$ $20x =4$ $x=\frac{4}{20}=\frac{1}{5}$ Substitute back to Equation $(2)$ $5(\frac{1}{5})+10y=4$ $1+10y=4$ $10y=3$ $y=\frac{3}{10}$
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