Answer
$(\displaystyle \frac{3}{2},3)$
Work Step by Step
Eliminate y,
$\left\{\begin{array}{lllll}
2x & -y & =0 & /\times 2 & \\
4x & +2y & =12 & & ...add
\end{array}\right.$
$8x=12$
$x=\displaystyle \frac{12}{8}=\frac{3}{2}$
Back - substitute:
$2x-y=0$
$2(\displaystyle \frac{3}{2})-y=0$
$3-y=0$
$y=3$
Solution: $(\displaystyle \frac{3}{2},3)$
Graphing, use x- and y-intercepts.
If the origin is the intercept, select another x and calculate y
$\left[\begin{array}{lll}
& & \\
& (y=0) & (x=1)\\
2x-\mathrm{y}=0 & 2x=0 & 2-y=0\\
& x=0 & y=2\\
& (0,0) & (1,2)\\
& & \\
& (y=0) & (x=0)\\
4x+2y=12 & 4x=12 & 2y=12\\
& x=3 & y=64\\
& (3,0) & (0,6)
\end{array}\right]$
