College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.1 - Systems of Linear Equations: Substitution and Elimination - 8.1 Assess Your Understanding - Page 555: 22

Answer

$x=-1$ $y=2$ $(-1,2)$

Work Step by Step

$x+3y = 5$ $(1)$ $2x-3y=-8$ $(2)$ Add Equation $(1)$ and Equation $(2)$ and we get $3x=-3$ $x=-1$ Substitute this back into Equation $(1)$ $-1+3y=5$ $3y=6$ $y=2$
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