College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 7 - Section 7.3 - The Ellipse - 7.3 Assess Your Understanding - Page 525: 69

Answer

$\frac{x^2}{100}+\frac{y^2}{36}=1$

Work Step by Step

The equation of the ellipse here has the form $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$, where $a\gt b\gt0$, the vertices are at $(0,-a)$ and $(0,a)$. Hence here by the text of the exercise, $a=\frac{20}{2}=10,b=6$, thus the equation is: $\frac{x^2}{10^2}+\frac{y^2}{6^2}=1\\\frac{x^2}{100}+\frac{y^2}{36}=1$
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