Answer
Center at $(0,0).$
Vertices at $(\pm 3,0).$
Foci at $(\pm\sqrt{5},0)$
Work Step by Step
$\displaystyle \frac{x^{2}}{3^{2}}+\frac{y^{2}}{2^{2}}=1,\quad $axis along the x-axis (greater numerator under $x^{2}$)
Apply the theorem:
Equation of an Ellipse: Center at $(0,0);$ Major Axis along the $x$ -Axis
An equation of the ellipse with center at $(0,0),$
foci at $(-c,0)$ and $(c,0),$
and vertices at $(-a,0)$ and $(a,0)$ is
$\displaystyle \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\quad $ where $a \gt b \gt 0$ and $b^{2}=a^{2}-c^{2}$
The major axis is the x-axis.
Center at $(0,0);$
Vertices at $(-a,0)=(-3,0)$ and $(a,0)=(3,0)$,
Find c from $b^{2}=a^{2}-c^{2}$
$c^{2}=a^{2}-b^{2}$
$c^{2}=9-4$
$c=\sqrt{5}$
Foci : $(\pm\sqrt{5},0)$