Answer
$$(x-2)^2+(y+3)^2=1$$
Work Step by Step
We know that the equation of a circle in standard form is given by:
$$(x-h)^2+(y-k)^2=r^2$$
Where (h, k) is the center of the circle and r is the radius.
Thus, for a circle with a center C=(2, -3) and a radius r=1, the equation becomes:
$$(x-2)^2+(y+3)^2=1$$
