Chapter 7 - Section 7.2 - The Parabola - 7.2 Assess Your Understanding - Page 514: 3

The solution set is {$-7,-1$}

To find the real solutions of $(x+4)^2=9$ with the Square Root Method, we take the square root of both sides and then solve for x. $\sqrt{(x+4)^2}=\sqrt{9}$ $x+4=\pm3$ $x=-4\pm3$ Therefore, the solution set is {$-7,-1$}