College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.6 - Logarithmic and Exponential Equations - 6.6 Assess Your Understanding - Page 465: 3

Answer

approximately $\color{blue}{-1.433}$

Work Step by Step

To approximate the solution to the given equation, treat the expressions on each side of the equation as a function then graph them on the same coordinate plane. Using a graphing utility, graph the following functions on the same coordinate plane: $y_1=x^3$ and $y_2=x^2-5$ (refer to the attached image below for the graph) Notice that the two graphs intersect at the point $(-1.433, -2.945)$. The solution to the given equation is the $x$-coordinate of the point of intersection of the graphs. Therefore, the solution to the given equation is approximately $\color{blue}{-1.433}$.
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