Answer
$y=Ce^{5x}-4$
Work Step by Step
Subtract by $\ln{C}$ on both sides:
$\ln{(y+4)} - \ln{C}=5x$
RECALL:
For positive real numbers M and N:
$\ln{M} - \ln{N} = \ln{\left(\dfrac{M}{N}\right)}$
Use the rule above to obtain:
$\ln{\left(\dfrac{y+4}{C}\right)}=5x$
RECALL:
$\ln{M}= y \longrightarrow e^y=M$
Use the rule above to obtain:
$e^{5x}=\dfrac{y+4}{C}$
Multiply by $C$ on both sides of the equation to obtain:
$C \cdot e^{5x} = C \cdot \dfrac{y+4}{C}
\\Ce^{5x} = y+4
\\y+4=Ce^{5x}$
Subtract by $4$ on both sides of the equation to obtain:
$y+4-4 = Ce^{5x}-4
\\y=Ce^{5x}-4$